Faraday's Law of Electromagnetic Induction: Practice Problem & Solution

Short Solution (Best for NEET):

To solve this problem, we apply the core principles of Faraday's Law of Electromagnetic Induction. Understanding the underlying formula is key to arriving at the correct answer below:

Induced emf is \(E = -d\phi/dt = BA\omega sin(\omega t)\). Magnetic flux is \(\phi = BA cos(\omega t)\). When \(\phi = 0\), \(cos(\omega t) = 0\), which implies \(sin(\omega t) =  1\). Thus, \(E\) is maximum. Both A and R are true, and R correctly explains A.