Ampere’s Law for Magnetostatics – Rankers Physics
Topic: Magnetic Effects of Current
Subtopic: Ampere's Circuital Law

Ampere’s Law for Magnetostatics

Assertion (A): In Ampere's law for magnetostatics \(\oint \vec{B} \cdot d\vec{l} = \mu_0 \sum I_{\text{i}}\) the current outside the Amperian loop is not included on the right side.
Reason (R): Magnetic field calculated using Ampere's law is due to inside as well outside the current of closed loop.
 
Both (A) & (R) are true and the (R) is the correct explanation of the (A)
Both (A) & (R) are true but the (R) is not the correct explanation of the (A)
(A) is true but (R) is false
Both (A) and (R) are false

Solution:

Assertion (A): Ampere's law \(\oint \vec{B} \cdot d\vec{l} = \mu_0 I_{\text{enclosed}}\) states that only currents passing through the Amperian loop contribute to the right-hand side. So, (A) is true.


Reason (R): The magnetic field (vec{B}) on the left-hand side of Ampere's law is the total field produced by all currents, both inside and outside the loop. So, (R) is true. However, R describes the nature of (vec{B}), not why only enclosed currents are counted on the right side. Thus, (R) is not the correct explanation of (A).

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