Solution:
Friction force action on the object is f=μ.N= μ.mg
Retardation of the block is a=μ.g = 0.5× 10 =5
Using equation of motion. Stopping distance = u^2/2a=(10 × 10)/( 2* 5)=10 m
Consider a car moving on a straight road with a speed of 10 ms-1. The distance at which car can be stopped is: [μ=0.5]
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