Friction: Practice Problem & Solution

Short Solution (Best for NEET):

To solve this problem, we apply the core principles of Friction. Understanding the underlying formula is key to arriving at the correct answer below:

Friction force action on the object is f=μ.N= μ.mg

Retardation of the block is  a=μ.g = 0.5× 10 =5

Using equation of motion. Stopping distance = u^2/2a=(10 × 10)/( 2* 5)=10 m