A trolley of mass 8 kg is standing on a frictionless surface inside which an object of mass 2 kg is suspended. A constant force F starts acting on the trolley as a result of which the string stood at an angle of 370 from the vertical (bob at rest relative to trolley) Then:
Solution:
Using concept of Pseudo force
a= g tanθ
⇒ a = g tan 37 = 10 ×3/4= 7.5 m/s^2
Using Equation of motion
⇒Fnet = 10×2.5 = 25 N
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