Nucleus: Practice Problem & Solution
Surface area of the nucleus (\(X^8\)) is \(A_0\), then surface area of nucleus (\(Y^{64}\) ) will be
Short Solution (Best for NEET):
To solve this problem, we apply the core principles of Nucleus. Understanding the underlying formula is key to arriving at the correct answer below:
Nuclear radius is given by \(R \propto A^{1/3}\), so the surface area is \(S \propto R^2 \propto A^{2/3}\). Thus, \(\frac{S_2}{S_1} = \left(\frac{64}{8}\right)^{2/3} = 8^{2/3} = 4\), meaning the surface area of the nucleus \(Y^{64}\) is \(4A_0\).
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