Solution:
The band gap is related to the threshold wavelength by the formula \(E_g = \frac{12400}{\lambda in A^0}\text{ eV}\). Substituting \(\lambda = 6200 A^0\), we get \(E_g = \frac{12400}{6200} = 2\text{ eV}\).
The electrical conductivity of a semiconductor increases when electromagnetic radiation of wavelength shorter than \(6200 A^0\), is incident on it. The band gap in (eV) for the semiconductor is
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