Solution:
Least count (LC) is given by \(text{LC} = 1text{ MSD} - 1text{ VSD}\). Since 20 VSD = 18 MSD, we have \(1text{ VSD} = 0.9text{ MSD}\). Thus, \(text{LC} = 0.1text{ MSD} = 0.1 times 0.2text{ mm} = 0.02text{ mm}\).
The vernier scale of a callipers is divided into 20 divisions which coincide with 18 main scale divisions. Each main scale division is 0.2 mm. The least count of the instrument is
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