Work done in non-uniform circular motion – Rankers Physics
Topic: Circular Motion
Subtopic: Dynamics of Circular Motion

Work done in non-uniform circular motion


Assertion (A): The work done by the net force on a particle during non-uniform circular motion is not equal to zero.
Reason (R): In case of non-uniform circular motion net force and elementary displacement are not perpendicular to each other.
 
Both (A) & (R) are true and the (R) is the correct explanation of the (A)
Both (A) & (R) are true but the (R) is not the correct explanation of the (A)
(A) is true but (R) is false
Both (A) and (R) are false

Solution:

In non-uniform circular motion, there is a tangential component of force, which causes a change in speed. Work done is `\(W = \int \vec{F}_{net} \cdot d\vec{r}\)`.
Since the net force is not always perpendicular to the elementary displacement `\(d\vec{r}\)` due to the tangential component, the work done by the net force is not zero. Both assertion and reason are true, and the reason correctly explains the assertion.

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