Assertion (A): A block of weight \(10 \text{ N}\) is pushed against a vertical wall by a horizontal force of \(15 \text{ N}\). The coefficient of friction between the wall and the block is \(0.6\). Then the magnitude of maximum frictional force is \(9 \text{ N}\).
Reason (R): For given system block will remain stationary.
Solution:
Normal force \(N = 15 \text{ N}\). Maximum static friction \(f_{\text{max}} = \mu_{\text{s}} N = 0.6 \times 15 = 9 \text{ N}\). So (A) is true. Weight of block is \(W = 10 \text{ N}\). Since \(W > f_{\text{max}}\), the block will slide down. So (R) is false.
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