A charged particle enters a magnetic field at right angles to the magnetic field. The field exists for a length equal to 1.5 times the radius of circular path of the circle. The particle will be deviated from its path by angle
\(sin^{-1} \left( \frac{2}{3} \right)\)
Solution:
Since the width of the magnetic field \(d = 1.5R > R\), the particle cannot cross the field to the other side. It will complete a semi-circular path inside the field and emerge from the same side it entered, yielding a deviation of \(180^\circ\).
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