Number of Electrons Removed to Acquire Charge

The number of electrons that should be removed from a metal coin such that coin acquires a positive charge of \(10^{-10}\text{ C}\) is

\(1.6 \times 10^{-19}\)

\(6.25 \times 10^{9}\)

\(6.25 \times 10^{8}\)

\(1.6 \times 10^{8}\)

Using quantization of charge, \(q = ne ⇒ n = \frac{q}{e} = \frac{10^{-10}}{1.6 \times 10^{-19}} = 6.25 \times 10^8\).