Solution:
The time to cross a river is \(t = \frac{d}{v \sin \theta}\), where \(theta\) is the angle with the river flow. For \(t\) to be minimum, \(sin \theta\) must be maximum, which occurs at \(\theta = 90^\circ = \frac{\pi}{2}\).
The time to cross a river is \(t = \frac{d}{v \sin \theta}\), where \(theta\) is the angle with the river flow. For \(t\) to be minimum, \(sin \theta\) must be maximum, which occurs at \(\theta = 90^\circ = \frac{\pi}{2}\).
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