Solution:
Total degrees of freedom \(f = 3 + 3 = 6\). Thus, \(C_v = \frac{f}{2} R = 3R\), and \(C_p = C_v + R = 4R\). Therefore, \(\gamma = \frac{C_p}{C_v} = \frac{4}{3}\).
A polyatomic molecule has 3 translational, 3 rotational degrees of freedom. The molar specific heat ratio \((\gamma = \frac{C_p}{C_v})\) for this gas is
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