Photoelectric Effects and deBroglie Equation: Practice Problem & Solution
In an experiment on photoelectric emission for incident light of wavelength \( 1.98 \times 10^{-7} \text{ m} \), stopping potential is found to be \( 2.5 \text{ V} \). What is maximum kinetic energy of emitted photoelectron?
Solution Explained:
To solve this problem, we apply the core principles of Photoelectric Effects and deBroglie Equation. Understanding the underlying formula is key to arriving at the correct answer below:
The maximum kinetic energy of emitted photoelectrons is related to the stopping potential by \( K_{\max} = e V_s \). Given \( V_s = 2.5 \text{ V} \), the maximum kinetic energy is simply \( 2.5 \text{ eV} \).
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