NEET Physics Question - Thermal Physics - Heat Transfer

The sun delivers about \( 1400 \text{ W/m}^2 \) of electromagnetic flux to Earth's surface. If the flux falls on a roof of dimensions \( 8\text{ m} \times 20\text{ m} \) normally, then total power incident on the roof will be

224 kW

112 kW

32 kW

96 kW

Solution:

Power is given by the product of intensity and area: \( P = I \times A \). Here \( I = 1400 \text{ W/m}^2 \) and \( A = 8\text{ m} \times 20\text{ m} = 160 \text{ m}^2 \). Therefore, \( P = 1400 \times 160 = 224,000 \text{ W} = 224 \text{ kW} \).

Rankers Physics

Power incident on a roof from solar flux

Solution:

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