Acceleration Due to Gravity and its variation: Practice Problem & Solution

Short Solution (Best for NEET):

To solve this problem, we apply the core principles of Acceleration Due to Gravity and its variation. Understanding the underlying formula is key to arriving at the correct answer below:

For two identical masses to move on a circular path of radius \(R\) about a common centre, they must always be diametrically opposite. The distance between them is \(2R\). Thus, \(F = \frac{GM^2}{(2R)^2} = \frac{GM^2}{4R^2}\).