Solution:
For four identical wires of resistance \(R\) connected in parallel, \(R_p = \frac{R}{4} = 0.25, \Omega ⇒ R = 1, \Omega\). In series, \(R_s = 4R = 4 \times 1, \Omega = 4, \Omega\).
For four identical wires of resistance \(R\) connected in parallel, \(R_p = \frac{R}{4} = 0.25, \Omega ⇒ R = 1, \Omega\). In series, \(R_s = 4R = 4 \times 1, \Omega = 4, \Omega\).
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