Dimensional Formula of E/G – Rankers Physics
Topic: Unit And Dimensions
Subtopic: Dimensions

Dimensional Formula of E/G

If \(E\) and \(G\) respectively denote Energy and Universal gravitational constant, then \(\frac{E}{G}\) has the dimensions of
\([M^2][L^{-2}][T^{-1}]\)
\([M^2][L^{-1}][T^0]\)
\([M][L^{-1}][T^{-1}]\)
\([M][L^0][T^0]\)

Solution:

Dimensions of energy \([E] = [M L^2 T^{-2}]\) and universal gravitational constant \([G] = [M^{-1} L^3 T^{-2}]\). Therefore, \([\frac{E}{G}] = \frac{[M L^2 T^{-2}]}{[M^{-1} L^3 T^{-2}]} = [M^2 L^{-1} T^0]\).

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