Ratio of Distances in Successive Seconds

A car starts from rest and moves with constant acceleration \(a\). The ratio of distances covered in the first second to the distance covered in third second is

\(1 : 2\)

\(2 : 1\)

\(3 : 1\)

\(1 : 5\)

Solution:

The distance covered in the \(n\)-th second from rest is given by \(S_n = frac{a}{2}(2n - 1)\). For the first second (\(n=1\)), \(S_1 = frac{a}{2}\), and for the third second (\(n=3\)), \(S_3 = frac{5a}{2}\). The ratio of \(S_1 : S_3\) is \(1 : 5\).

Ratio of Distances in Successive Seconds

Solution:

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