Force Acting on Current Carrying Conductor: Practice Problem & Solution
A long straight wire carries an electric current \(4\text{ A}\). The magnetic induction at a perpendicular distance \(2\text{ m}\) from the wire is
Short Solution (Best for NEET):
To solve this problem, we apply the core principles of Force Acting on Current Carrying Conductor. Understanding the underlying formula is key to arriving at the correct answer below:
The magnetic field near a long straight wire is given by \(B = \frac{\mu_0 I}{2\pi r}\). Substituting \(I = 4\text{ A}\) and \(r = 2\text{ m}\) with \(\mu_0 = 4\pi \times 10^{-7}\text{ T m/A}\) gives \(B = \frac{4\pi \times 10^{-7} \times 4}{4\pi} = 4 \times 10^{-7}\text{ T}\).
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