Temperature Gradient in a Rod – Rankers Physics
Topic: Thermal Physics
Subtopic: Heat Transfer - Conduction and Convection

Temperature Gradient in a Rod

The temperature gradient in a rod \(0.5\text{ m}\) long is \(80^\circ\text{C/m}\). If temperature of hotter end is \(30^\circ\text{C}\), then temperature of the colder end will be
\(0^\circ\text{C}\)
\(20^\circ\text{C}\)
\(10^\circ\text{C}\)
\(-10^\circ\text{C}\)

Solution:

Temperature gradient is defined as \(\frac{T_{\text{hot}} - T_{\text{cold}}}{L}\). Substituting the values, \(80 = \frac{30 - T_{\text{cold}}}{0.5}\). This simplifies to \(30 - T_{\text{cold}} = 40\), which gives \(T_{\text{cold}} = -10^\circ\text{C}\).

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