Solution:
\[ x= A sin\left( \omega t \right) \]
x= (1cm) sin (2π/8t)= (1 cm ) sin ( π/4t)
v=dx/dt= π/4 cos( π/4t)
a= dv/dt = -(π/4)²sin (π/4t)
a= -(π/4)²sin (π/4×4/3)= -√3/32π² cm/s²
The x-t graph of a particle undergoing simple harmonic motion is shown below. The acceleration of the particle at t = 4/3 s is :
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