Water Height in Tank with Two Holes – Rankers Physics
Topic: Solid and Fluids
Subtopic: Fluid Dynamics

Water Height in Tank with Two Holes

A water tank resting on the floor has two small holes vertically one above the other. The holes are \(h_1\) \(text{cm}\) and \(h_2\) \(text{cm}\) above the floor. How high does water stand in the tank if the jets from the holes hits the floor at the same point ?
\(h_1 + h_2\)
\(h_2 - h_1\)
\(\frac{h_1^2 + h_2^2}{2}\)
\(\frac{h_2^2 - h_1^2}{2}\)

Solution:

For equal horizontal range, the height \(H\) of the water level in the tank must satisfy \(h_1(H - h_1) = h_2(H - h_2)\). Solving for \(H\) gives \(H(h_2 - h_1) = h_2^2 - h_1^2\), which simplifies to \(H = h_1 + h_2\).

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