Solution:

Dielectric strength is the maximum field \(E_{\text{max}} = 2\text{ kV/mm} = 2 \times 10^6\text{ V/m}\). For thickness \(d = 50 \mu\text{m} = 5 \times 10^{-5}\text{ m}\), the maximum potential difference is \(V_{\text{max}} = E_{\text{max}} \times d = 2 \times 10^6 \times 5 \times 10^{-5} = 100\text{ V}\).