NEET Physics Question - Kinematics - Ground to Ground Projectile

At what angle to the horizontal should an object be projected so that the maximum height reached is equal to half of the horizontal range?

\(\tan^{-1} (1)\)

\(\tan^{-1} (2)\)

\(\tan^{-1} (3)\)

\(\tan^{-1} (4)\)

Solution:

We require \(H = \frac{R}{2}\). Using the formulae \(H = \frac{u^2 \sin^2 \theta}{2g}\) and \(R = \frac{u^2 \sin 2\theta}{g}\), we get \(\frac{u^2 \sin^2 \theta}{2g} = \frac{u^2 \sin\theta\cos\theta}{g} ⇒ \tan\theta = 2 ⇒ \theta = \tan^{-1}(2)\).

Rankers Physics

Angle of Projection

Solution:

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