Solution:
The maximum speed of a particle in simple harmonic motion is given by \(v_{\text{max}} = A\omega\). Since \(\omega = \frac{2\pi}{T}\), we get \(v_{\text{max}} = \frac{2\pi A}{T}\).
For a particle executing simple harmonic motion, the amplitude is \(A\) and time period is \(T\). The maximum speed will be:
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