Faraday's Law of Electromagnetic Induction: Practice Problem & Solution
Two coils have mutual inductance \(0.005\text{ H}\). The current changes in the first coil according to equation \(I = I_0 \sin \omega t\), where \(I_0 = 10\text{ A}\) and \(\omega = 100\pi\text{ rad/s}\). The maximum value of EMF in the second coil is:
Short Solution (Best for NEET):
To solve this problem, we apply the core principles of Faraday's Law of Electromagnetic Induction. Understanding the underlying formula is key to arriving at the correct answer below:
Induced EMF is \(e = M \frac{dI}{dt} = M I_0 \omega \cos \omega t\). Maximum EMF \(e_{max} = M I_0 \omega = 0.005 \times 10 \times 100\pi = 5\pi\text{ V}\).
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