Topic: Electromagnetic Waves
Subtopic: Properties of EM Waves
In an electromagnetic wave, (travelling in vacuum) \(E = 1.2 \sin(2 \times 10^6 t - kx)\text{ N/C}\). Find the value of maximum intensity of magnetic field:\(4 \times 10^{-8}\text{ A/m}\)
\(\frac{10^{-3}}{\pi}\text{ A/m}\)
\(4 \times 10^{-9}\text{ A/m}\)
\(\frac{10^{-2}}{\pi}\text{ A/m}\)
Solution:
Maximum magnetic field \(B_0 = \frac{E_0}{c} = \frac{1.2}{3 \times 10^8} = 4 \times 10^{-9}\text{ T}\). The intensity of magnetic field is \(H_0 = \frac{B_0}{\mu_0} = \frac{4 \times 10^{-9}}{4\pi \times 10^{-7}} = \frac{10^{-2}}{\pi}\text{ A/m}\).
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