Potential Difference Between Airplane Wing Tips – Rankers Physics

Motional EMF: Practice Problem & Solution

An aeroplane in which the distance between the tips of the wings is \(50\text{ m}\) is flying horizontally with a speed of \(360\text{ km/hr}\) over a place where the vertical component of earth's magnetic field is \(2 \times 10^{-4}\text{ Wbm}^{-2}\). The potential difference between the tips of the wings would be:
\(0.1\text{ V}\)
\(1.0\text{ V}\)
\(0.2\text{ V}\)
\(0.01\text{ V}\)

Solution Explained:

To solve this problem, we apply the core principles of Motional EMF. Understanding the underlying formula is key to arriving at the correct answer below:

Induced EMF is \(e = B_v l v\). Converting speed: \(v = 360\text{ km/h} = 100\text{ m/s}\). Thus, \(e = (2 \times 10^{-4}) \times 50 \times 100 = 1.0\text{ V}\).

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