Solution:
In an ideal transformer, input power equals output power: \(V_p I_p = V_s I_s\). Therefore, \(I_s = \frac{V_p I_p}{V_s} = \frac{220 \times 5}{22000} = 0.05\text{ A}\).
In a step up transformer, the voltage in the primary is \(220\text{ V}\) and the current is \(5\text{ A}\). The secondary voltage is found to be \(22000\text{ V}\). The current in the secondary coil (neglect losses) is:
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