Co-efficient of Restitution of a Rebounding Particle – Rankers Physics

Collision: Practice Problem & Solution

A particle is dropped on the ground from a height \( 36\text{ m} \) and after striking the ground it rebounds to a height of \( 16\text{ m} \). Then the co-efficient of restitution of the collision with the ground is:
\( \frac{1}{3} \)
\( \frac{1}{2} \)
\( \frac{2}{3} \)
\( \frac{3}{2} \)

Solution Explained:

To solve this problem, we apply the core principles of Collision. Understanding the underlying formula is key to arriving at the correct answer below:

The coefficient of restitution \( e \) for a vertical rebound is given by \( e = \sqrt{\frac{h_{\text{rebound}}}{h_{\text{initial}}}} \). Substituting the given values, \( e = \sqrt{\frac{16}{36}} = \frac{4}{6} = \frac{2}{3} \).

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