Solution:
To convert a galvanometer to a voltmeter, a high series resistance \( R \) is added: \( R = \frac{V}{I_g} - G \). Substituting values, \( R = \frac{10}{20 \times 10^{-3}} - 100 = 500 - 100 = 400\ \Omega \).
To convert a galvanometer to a voltmeter, a high series resistance \( R \) is added: \( R = \frac{V}{I_g} - G \). Substituting values, \( R = \frac{10}{20 \times 10^{-3}} - 100 = 500 - 100 = 400\ \Omega \).
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