Solution:
Velocity is given by differentiating displacement with respect to time: \(v = \frac{ds}{dt} = 16t + 3\). For initial velocity, substitute \(t = 0\), which gives \(v = 3\text{ cm/s}\).
The displacement \(s\) of a point moving in a straight line is given by : \(s = 8t^2 + 3t - 5\) where \(s\) is in cm and \(t\) in s. The initial velocity of the particle is :
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