Electric Field outside a Conducting Sphere – Rankers Physics
Topic: Electrostatics
Subtopic: Electric Field

Electric Field outside a Conducting Sphere

If a conducting sphere of radius R is charged. Then the electric field at a distance \(r\) (\(r > R\)) from the centre of the sphere would be, (V = potential on the surface of the sphere)
\(\frac{RV}{r^2}\)
\(\frac{V}{r}\)
\(\frac{rV}{R^2}\)
\(\frac{R^2 V}{r^3}\)

Solution:

The electric potential at the surface of a conducting sphere is \(V = \frac{kQ}{R} \implies kQ = VR\). The electric field at any point outside the sphere (\(r > R\)) is \(E = \frac{kQ}{r^2} = \frac{VR}{r^2}\).

Leave a Reply

Your email address will not be published. Required fields are marked *