Rankers Physics

The figure shows a horizontal block of mass M suspended by two wires A and B. The centre of mass of the block is closer to B than A. (i) Is the magnitude of the torque due to wire A is greater, less or equal to that due to B w.r.t. centre of mass ? (ii) Which wire A or B exerts more force on the block ? Image related to

(i) greater (ii) B
(i) equal (ii) B
(i) less (ii) A
(i) greater (ii) A

Solution:

As the object is in rotational equilibrium, Net torque acting on the object is zero.

so,  Torque of TA = Torque of TB

TAXA= TBXB

\[ \frac{T_{A}}{T_{B}}=\frac{X_{B}}{X_{A}} \]

\[ X_{B} < X_{A} \]

\[ T_{A} <  T_{B} \]

Leave a Reply

Your email address will not be published. Required fields are marked *

Similar Questions

Explore conceptually related problems

1. A ladder of length \(\ell\) and mass m is placed against a smooth vertical wall but the ground is not smooth. Coefficient of friction between the ground and the ladder is \(\mu\). The minimum angle \(\theta\) with ground at which the ladder will stay in equilibrium is :
2. Find the torque about the origin when a force of $3 \hat{j} \text{ N}$ acts on a particle whose position vector is $2 \hat{k} \text{ m}$. (2020)
3. A wheel having moment of inertia $2 \text{ kg-m}^2$ about its vertical axis, rotates at the rate of $60 \text{ rpm}$ about the axis. The torque which can stop the wheel's rotation in one minute would be: (2004)
4. The moment of inertia of a body about a given axis is $1.2 \text{ kgm}^2$. Initially, the body is at rest. In order to produce a rotational kinetic energy of $1500 \text{ joule}$, an angular acceleration of $25 \text{ rad/sec}^2$ must be applied about that axis for a duration of: (1990)
5. The force acting on a particle is \( \vec{F} = \hat{i} + 2\hat{j} + 3\hat{k} \text{ N} \). Find the torque (in N m) of this force about origin if position vector of the particle is \( \vec{r} = 7\hat{i} + 3\hat{j} + 5\hat{k} \text{ m} \).