NEET Physics Question - Laws of Motion

A body of mass m is kept on a rough horizontal surface (coefficient of friction = μ). A horizontal force is applied on the body, but it does not move. The resultant of normal reaction and the frictional force acting on the object is given by F, where F is:

F = mg

F = μmg

F = mg + μmg

F ≤ mg(1 + μ²)^1/2

Solution:

The forces acting on the body are: Normal reaction (N $= m g)$ (upward) and Friction force f $\leq μ m g$ (opposing applied force)

The resultant force is:

$F = \sqrt{N^2 + f^2} = \sqrt{mg^2 + (\mu mg)^2} = mg \sqrt{1 + \mu^2}$

$F \leq mg(1 + \mu^2)^{1/2}$

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