Rankers Physics
Topic: Laws of Motion
Subtopic: Pseudo Force

A block of mass m is in contact with the cart. The coefficient of static friction between the block and the cart is ü. The acceleration a of the cart that prevent the block from falling will be     Image related to
a> (mg/ü)
a> (g/ü.m)
a ≥ (g/ü)
a ≤ (g/ü)

Solution:

The condition to prevent the block from falling is that the friction force must be at least equal to the weight of the block:

fsmgf_s \geq mg

Since static friction is given by fs=μNf_s = \mu N and the normal force is due to pseudo force N=maN = ma, we get:

μmamg\mu ma \geq mg

Dividing both sides by μm\mu m:

agμa \geq \frac{g}{\mu}

Thus, the required acceleration of the cart is agμa \geq \frac{g}{\mu}.

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