Rankers Physics
Topic: Kinematics
Subtopic: Projectile from Height

An object is projected horizontally from a 100 m high cliff with a speed of 10 m/s. What will be its velocity 1 second after projection?
10 m/s
20 m/s
10√2 m/s
10√3 m/s

Solution:

Given:

vx=10v_x = 10

m/s,

g=10g = 10

m/s²,

t=1t = 1

s

Vertical velocity:

vy=gt=10v_y = g t = 10

m/s

Resultant velocity:

 

v=vx2+vy2=102+102=10√2  m/sv = \sqrt{v_x^2 + v_y^2} = \sqrt{10^2 + 10^2} = 14.1 \text{ m/s}

 

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