Rankers Physics
Topic: Solid and Fluids
Subtopic: Fluid Statics

The reading of spring balance when a block is suspended from it in air, is 60 N. This reading is changed to 40 N when the block is immersed in water. The specific gravity of the block is :
3
2
6
3/2

Solution:

Solution:

  • Loss of weight in water = $$\text{Weight in air} - \text{Weight in water} = 60\text{ N} - 40\text{ N} = 20\text{ N}$$

  • Specific gravity = $$\frac{\text{Weight in air}}{\text{Loss of weight in water}} = \frac{60}{20} = 3$$

Therefore, the specific gravity of the block is 3 (Option 1).

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