For a body of mass 1 kg U-x graph is shown in If the body is released from rest at x = 2m, then its speed when it crosses x = 5m is 2 √2 ms–11 ms–12 ms–14 ms–1Solution:From Principal of Conservation of Energy Ui + Ki = Uf + Kf 10 +0 = 2 + ½v² ⇒ v ² = 16 ⇒ v = 4 m/s
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