Solution:
Net force is 6N-3N= 3N
Accleration of the system is 3N/3Kg = 1 m/s^2
Net Force on 1kg object is N1 - 3= 1*1 so, N1 = 4N
Two forces of 6N and 3N are acting on the two blocks of 2kg and 1 kg kept on frictionless floor. What is the force exerted on 2kg block by 1 kg block?
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