Solution:
Given:
- Horizontal distance between buildings \( x = 30 \, \text{m} \)
- Height difference \( h = 150 - 27.5 = 122.5 \, \text{m} \)
- Use \( h = \frac{1}{2} g t^2 \) to find time \( t \):
\[
122.5 = \frac{1}{2} \times 10 \times t^2 \quad \Rightarrow \quad t^2 = 24.5 \quad \Rightarrow \quad t = \sqrt{24.5} \approx 4.95 \, \text{seconds}
\]
Horizontal velocity \( v = \frac{x}{t} = \frac{30}{4.95} \approx 6.06 \, \text{m/s} \).
Thus, the required speed is \( {6.0 \, \text{m/s}} \).
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