Solution:
The relative velocity of the bird with respect to the observer in the train is found by combining the bird's velocity (south) and the train's velocity (east) using the Pythagorean theorem.
\[
v_{\text{relative}} = \sqrt{(40^2 + 40^2)} = \sqrt{3200} = 40\sqrt{2} \, \text{km/h}
\]
The direction is \( 45^\circ \) south of west.
Thus, the relative velocity is:
\[ {40\sqrt{2} \, \text{km/h} \text{ at } 45^\circ \text{ south of west}}
\]
Leave a Reply