Solution:
For Second Half of Journey
\[ V_{av}=\frac{3+5}{2}= 4 m/s \]
\[ V_{av}= \frac{2\times 2 \times 4}{2+4}= \frac{8}{6}= \frac{4}{3} \]
A body of mass m moving along a straight line covers half the distance with a speed of 2 ms–¹. The remaining half of distance is covered in two equal time intervals with a speed of 3 ms–¹ and 5 ms–¹ respectively. The average speed of the particle for the entire journey is
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