A car moves a distance of 200 m. It covers first half of the distance at speed 60 kmh–¹ and the second half at speed v. If the average speed is 40 kmh–¹, the value of v is30 kmh–¹13 kmh–¹20 kmh–¹40 kmh–¹Solution:\[ V_{av}= \frac{2V_{1}.V_{2}}{V_{1}+V_{2}}\] \[ 40= \frac{2\times 60\times V_{2}}{ 60+V_{2}} \] \[ V_{2}= 30 m/s \]
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