Solution:
Given, x = t²/2 differentiating v=dx/dt= t
Initial Speed Vi= 0 m/s
Final Speed Vf= 3 m/s
From Work Energy Theorem, Work done is equal to change in kinetic energy
So, Work Done = ½m (Vf² - Vi²)= 1/2 × 1× (9-0) = 4.5 J
The position of a particle of mass 1 kg moving along x-axis at time t is given by x=t²/2. The work done by the force from t=0 to t=3 sec
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