Solution:
From Principal of conservation of Energy in absence of non-conservative forces,
Ui+ Ki= Uf+ Kf
½KL²+ 0 = ½mv²
⇒v= √(KL²/m)
Momentum is P= m.v = m. √(KL²/m) =(mK)½ L
The block of mass M moving on the frictionless horizontal surface collides with the spring of spring constant K and compresses it by length L. The maximum momentum of the block after collision is
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