Rankers Physics
Topic: Work Energy and Power
Subtopic: Potential Energy & Equilibrium

A uniform chain has a mass m and length l. It is held on a frictionless table with one-sixth of its length hanging over the edge. The work done in just pulling the hanging part back on the table is
mgl/72
mgl/36
mgl/12
mgl/6

Solution:

mass of hanging portion = m/6

Potential energy of handing portion = m/6×g×(-l/12)= -mgl/72

Work done by external agent is negative of change is Potential Energy = mgl/72

Leave a Reply

Your email address will not be published. Required fields are marked *