Rankers Physics
Topic: Work Energy and Power
Subtopic: Principal of Conservation of Energy

A body is released from position A as shown in figure. The speed of body at position B isImage related to
10 m/s
10√2 m/s
20 m/s
20√2 m/s

Solution:

From Principal of Conservation of Energy

Ui + Ki= Uf+ Kf

⇒ mg(50) + 0 = mg(10) + ½ m v²

⇒ v² = 800 

⇒ v = 20√2 m/s

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