Solution:
Potential Energy is U = ax² – bx³. For Equilibrium F = -dU/dx
⇒ dU/dx= 2ax- 3bx²=0
⇒ x = 2a/3b
In a certain field, the potential energy is U = ax² – bx³, where a and b constants. The particle is in stable equilibrium at x equal to
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